11x^2-4=-2x+4+10x

Solution for 11x^2-4=-2x+4+10x equation:

11x^2-4=-2x+4+10x

We move all terms to the left:

11x^2-4-(-2x+4+10x)=0

We add all the numbers together, and all the variables

11x^2-(8x+4)-4=0

We get rid of parentheses

11x^2-8x-4-4=0

We add all the numbers together, and all the variables

11x^2-8x-8=0

a = 11; b = -8; c = -8;
Δ = b2-4ac
Δ = -82-4·11·(-8)
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{26}}{2*11}=\frac{8-4\sqrt{26}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{26}}{2*11}=\frac{8+4\sqrt{26}}{22}
$